Refining The Dual Cones for Accuracy
[Reducing the document to the bare minimum for engineering accuracy.]
Why Didn't My First Sets of Dual Cone Builds Work?
While my calculations for wire size were very close to theory, the EM
resonance
was off due to wire size plus insulation being too large to
fit the space field resonance desired.
To make the cones resonant at 333 kHz I had to make them 24.25 inches
in height, with the selected wire type.
Specification was 19.56 inches in height. This is a +12.4 percent error
in wire size to fit the vibrational model, to get the correct EM
resonance.
Adding a capacitor at the center point of the smaller cones did not
compensate for a longer wire length necessary, as the coupling to the
background field was not distributed along the cone properly to
oscillate up EM with the vibration field.
The cones themselves, provide both distributed capacitance and inductance, but as well, they must
also be resonant within a vibrational
distance wavelength from the background field.
All three of these parameters must fit the design for the cones to work
correctly.
I cut a 1/2 inch diameter copper tube to 44 inches, and note it does
vibrate up very nicely from the background field, and feels electric,
as well as vibrating at very high frequency.
This is the length of one side of the tetrahedron Bashar
describes. The height is 3 foot, or 36 inches, the sides are 44 inches.
This is the energy form we are tapping into.
When I bring this copper pipe near my larger dual cones that do
resonate up at 333 kHz, the cones vibrate up nicely.
However the height of the cones are 4.69 inches over spec,
from what they should be, and do not fall in the "sweet spot" they
should.
This means I need to find smaller wire,
physically, but maintain the higher
dielectric constant of the insulation to keep the frequency of
resonance low.
I would also submit, there is no electronics formula out there, as of
yet, that can be used to design the necessary properties of these dual
cone systems.
Resonance frequency at the EM level must be found by trail and error
for the wire type selected. Ham radio methods, with many people
experimenting.
My first run provided much necessary information, as to how to proceed,
but we are still left with trial and error factors on a final build
that will work., based on past builds and measurements.
Here are the factors of the design.
1 - The cone height 19.5756 inches
2 - The cone apex angle 33 degrees
3 - The cone wiring surface area 371.91513 square inches
4 - The size of the wire plus insulation which will determine if the
wire can all fit in the correct space
5 - The dielectric constant of the wire which will shorten the resonant
wire length
6 - The actual wire length, which will resonate the
EM frequency
7 - The Dual cones EM resonance frequency 333 kHz, after assembly and
cross connection
I noted in my first document, the correct wire size may be difficult,
or more expensive to locate.
Teflon coated wire, had the necessary dimension qualities, insulation
is thinner, with moderate dielectric constant, but was very
high in
cost.
Calculation Review In Depth
Fractal Calculation
1.87 mm is the wavelength of the background field resonance in free
space.
Now dealing with this length as a fractal vibration we start summing it
to see how it fits the tetrahedron that Bashar offered us.
Perfect Tetrahedron height
1.87 mm x 489 = 914.43 mm = 36.001 inches
This is a background coupling length at 489 times the fractal resonance of
the space field.
Perfect Tetrahedron side length
1.87 mm x 598 = 1118.26 mm = 44.026
inches This is another background coupling at 598 times the fractal resonance of
the space field.
I cut each of these lengths above to verify they do vibrate up in
copper tubes, and I can feel them with the palms.
These are the dimensions of the Source
field resonance we are tapping into.
Energy on a fractal breaks down to the
wavelength of the prime factors of the segment length stack
number.
The vibration rises in frequency with more length, opposite as the EM
wave where vibration frequency drops with longer length, and in this
inversion of time into space is the real formula we are working with.
This effect of vibration rising in frequency stops when you hit a prime
number length of the base fractal, causing a down shift of the
higher vibration rate to a lower frequency.
489 = 163 x 3 both prime
numbers. These will fracture into 3 lengths of exactly 1 foot in
oscillation at the vibration level.
163 x
1.87 = 304.81 mm = 30.481 cm =12.000 inches.
598 = 2 x 13 x 23 all
prime numbers. This fracturing is more complex with 3 different lengths
of harmonic vibration present in the vibration field
1.87 x 13 = 24.31 mm = 2.431 cm
= 0.95708661 inch
1.87 x 23 = 43.01 mm = 4.301 cm = 1.693307 inch
Geometry Calculation
Two different interpretations of Bashars descriptions of deriving the
cone dimensions from the tetrahedron form have been noted, shown in the
diagrams below.
The calculations here are from
the lower interpretation. Believing the cone must fit inside the
platonic solid form, as the cutaway on the right shows of the top view,
where the cone intersects the tetrahedrons sides, the wire stays inside
the form and cannot touch the outer corners of the tetrahedron. Note the
difference is about 5.5 inches in the two cones heights.
Find the actual cone dimensions
accurately:
We begin with the dihedral angle of the tetrahedron form 70.53 degrees
from geometry references.
This is the angle between the planar surfaces as they meet on the edges
of the tetrahedron as located in the drawing above.
Table of polyhedron dihedral angles
Star Tetrahedron
From the star tetrahedron URL above, at the bottom of it's page, we
find the angle very accurately calculated out to 70.52877937 degrees.
The other angle, where the star tetrahedrons opposing rotations hit a
sphere, also used below, 19.4712263 degrees [for reference].
This is a point on the earths sphere said to be very active with torsion field energy, latitude 19.47 degrees.
For now simply note these two special angles add up to exactly 90 degrees and are used in the calculations below.
Also the relation of the long edge length 44" to the height of the
tetrahedron 36" [ height = sqrt (2/3) x edge length. ]
Wikipedia Tetrahedron
The first image below is a tetrahedron shown, with the height from the tip extended down to the center of the bottom, forming
the triangles we will use to calculate the cone dimensions. From
this we solve for the length of x, which will be one side of the
smaller triangle the cone fits in. x = sin(60) * 44.026" =
38.127".
The second image below is the small triangles in this area turned flat
to the
screen with angles and known lengths plotted for reference.
Tetrahedron height = 36.001" for a perfect space resonance. The height
hits the bottom line at 1/3 of it's length, from the geometry data
found
on line.
The bottom two lengths are now derived from the 38.127" length cut into
thirds. 12.708234 and 25.418766 inches.
The third image below at the bottom is a blow up of the small triangle
forming the cones angles and lengths, that will just set inside the
larger tetrahedron in 3D.
x y and z are the values we need to accurately find, to construct the
cone with a 33 degree apex angle at the tip.
Cone Set 1
From the lower diagram, solving simultaneous equations, down the
middle then continued up on the right, we come up with the actual cone
dimensions x y z.
33
degree Cone
height
z
19.5756 " = 49.7220 cm
side x
20.41636 " = 51.8575 cm
radius at base
y 5.79856" =
14.72834 cm
diameter
at base 2y 11.59712" = 29.45668 cm
Up to this point everyone seems to be in agreement and
understanding fairly closely. However, here is where many get into
totally
absurd spin offs, that cannot begin to work for an EM extraction.
Winding a coil with random size of wire and turns, will not produce a
resonating EM field.
We must follow up with the Electrical Specifications to match the
geometry and resonate the Electro-Magnetic field at 333kHz in order
for the background vibration field to couple to it.
Find the area of the surface of the cone that the wire will have to
geometrically fit inside
Area of a cones surface =
pi * r * s [s = side length]
r = 5.79856 "
s = 20.41636 "
Area =
371.91513 square inches
This is now our
Geometric Space Resonant wiring surface.
The wire must fit in this area.
We can use this formula to test our coil designs for a good fit.
Wire length times wire diameter = Cone surface area
[W len * W dia =
371.91513 square inches.]
Cone Set 2
In the second case, we have the larger interpretation providing the data below.
This is the size of my cone set 2 data, the larger cones.
EM Resonance
Parameters of Consequence
The coils we wind on the surface area of the two cones, when connected
together top and bottom, must vibrate up the
electromagnetic field at 333 kHz
exactly, as a current flow. [333000 Hz]
Here is the frequency response of the target coil system
The coil system has a negative dip at resonance, it's reactance drops drastically and sharply at the one frequency it is tuned to.
The coil reduces noise by eliminating "currents" of off resonant frequencies, and only passes one frequency as a "current source."
A coil at the center, as a secondary, has a reversed curve as above,
and converts the signal to a peaking voltage at resonance.
See diagrams below.
The resonant frequency can vary depending on the impedance of the feed to it.
Fed into a detector and audio amplifier, it can produce an output that has less background noise then a commercial radio receiver, and pick up stations with greater clarity.
See diagram below.
This shows how the coil system is
different then conventional coils.
The distributed capacitance and
inductance along the windings change the resonant qualities of
the coil system inverting it to resemble a series tuned circuit.
Wire Choices
Wire diameter times Wire length = Wire surface area
The Wire must fit on cone surface area, as close as
possible for the greatest coupling of energy on the "sweet spot" of the
vibration nodes.
Once we know the length of the
resonant wire, we can calculate the maximum wire size diameter by
dividing it's length into the surface area.
Wire plus insulation must be equal to or less then this diameter value.
Wire max diameter = 371.91513 /
Wire Length
Wire dielectric constant or VOP [velocity of propagation] x
wire length = EM wavelength / 2 at 333 kHz
To find the length of the wire, we must multiply the VOP [velocity of
propagation] times the
free space resonance wavelength of a 333 kHz EM resonant RF field, then
divide by 2 to get the 1/2 wave length of each coil.
c = light velocity = 299792458 meters per second
Wire Length = VOP * (c / 333000 Hz) / 2)
Wire Length = VOP * (900.27765 meters / 2)
First wire length calculation free space dipole antenna resonance at
333000 Hz
Wire Length =
VOP * 450.1388258 meters in free space
Convert to cm then Inches then Feet
Wire Length = VOP * 45,013.88258 centimeters
Wire Length = VOP * 17,722.001 inches
Wire Length =
VOP * 1,476.833417979 feet
We end up with a range of possible
wire lengths based on past experience with insulated wire for a
free space dipole antenna.
.5 to .3 VOP
W len = .5 * 1476.833417979 feet = 738.4167089 feet
W len = .3 * 1476.833417979 feet = 443.0500254 feet
EM resonance on Completed Joined Cones = 333 kHz exactly
The wire length on a wound coil is much
shorter then the free space antenna wire length.
In some coil calculators it is 1/4 wave rather then 1/2 wave, as the
ends are terminated rather then opened inverting the reflected signal
polarity.
This cuts our wire length in half again for the dual coil system.
220 to 369 feet range for wire lengths with high moderate dielectric insulation
Early testing showed this is likely true.
500 feet PVC wire on a shipping spool resonated at 153.843 kHz
[less then 1/2 what is calculated above for a free space
antenna]
Two of these coils in parallel connection resonated at 163.934 kHz
Only a 10.091 kHz increase and no where even near 333.000 kHz target
resonance, from a free space dipole with opened ends.
166.5 kHz is 1/2 of 333 kHz
Thus for a 333 kHz wave on a dual coil system, using this wire, we would expect about 255 feet should be close for each coil.
The resonant frequency on these cones is a lower resistance, like a
series resonant circuit. As you tune across the band the voltage will
dip sharply at resonance, indicating a higher current condition as a
load.
A center positioned secondary coil will peak in voltage at the same time. In this sense it acts like a transformer.
[I have 3 dual cone sets to
measure the following parameters for the 2 mm diameter wire that was
used]
Wire length per cone
Number of turns per cone
R0 frequency - per finished cones
in parallel
After I get this data recorded here, we can move forwards with a
next best guess on wire choice and quantity for a more accurate build
of the dual cone system.
Notes:
On the dual cone assembly the ends of the antenna are shorted, so the
voltage wave will flip over or toggle on the two ends as it is
reflected back and forth.
This makes the coil system an oscillator, rather then an antenna,
technically.
It is all about having the 333 kHz EM wave move end to end of the coll
system at exactly the correct timing, split through both coils, so that
voltage nodes develop on both ends of the coils simultaneously, and
current nodes at the center crossing point.
As the voltage wave starts at one end of the coils it must move to
the other end at 1/2 wavelength and then return at 1 wavelength to
resonate as an oscillator, or generator of AC power.
Both coils must have the same exact wire length as well for this to
happen consistently over time, otherwise there will be drift of the
nodes and then loss of synchronization with the background space field.
Sloppy wiring, or inconsistency between the two coils will likely cause
the voltage nodes to drift out of sync. Anything less then perfection
will likely not self oscillate.
To compensate for this, the joining wires at one end may be lengthened
or shortened.
These
are the parameters of consequence, which will "make or break" the
system resonance, and the conversion of vibration into EM field power.
Cone Set 2 Data
Maximizing the Earth Ground Wave
There are several suggestions that can increase the vibrational energy
in the dual cone system, that have been shown to work on the vibration
side of the energy form.
The first is to mount the dual cones over an earth node. The vibration energy
that actually powers the field comes from the earths mass.
Mount them centered over an earth node and then raise and lower them
for a peak of vibration on the cones.
The next possibility is to set up a copper tube tetrahedron antenna
system with 44.026" sides.
If set up over an earth node at correct height, this antenna system
should greatly increase the vibration field strength of the dual cones.
The apex is routed via copper wire to a tuning gap over the top of the
cones cross wired ends. The gap can be any multiple of 1.87 mm, and the
energy should jump into the cones.
This will keep raw voltage off the antenna, and yet allow a free flow
of vibration energy across the gap. If you need more spacing increase
it by steps of 1.87 mm [background resonance of the Ether medium].
The same can be at done the bottom of the cone into an earth ground,
allowing the voltage on the cones to be free of the earth, and still
pass the vibration energy through them.
Dave L 3 / 14 / 2015