# Refining The Dual Cones for Accuracy

[Reducing the document to the bare minimum for engineering accuracy.]

### Why Didn't My First Sets of Dual Cone Builds Work?

While my calculations for wire size were very close to theory, the EM resonance was off due to wire size plus insulation being too large to fit the space field resonance desired.
To make the cones resonant at 333 kHz I had to make them 24.25 inches in height, with the selected wire type.
Specification was 19.56 inches in height. This is a +12.4 percent error in wire size to fit the vibrational model, to get the correct EM resonance.

Adding a capacitor at the center point of the smaller cones did not compensate for a longer wire length necessary, as the coupling to the background field was not distributed along the cone properly to oscillate up EM with the vibration field.
The cones themselves, provide both distributed capacitance and inductance, but as well, they must also be resonant within a vibrational distance wavelength from the background field.
All three of these parameters must fit the design for the cones to work correctly.

I cut a 1/2 inch diameter copper tube to 44 inches, and note it does vibrate up very nicely from the background field, and feels electric, as well as vibrating at very high frequency.
This is the length of one side of the tetrahedron Bashar describes. The height is 3 foot, or 36 inches, the sides are 44 inches. This is the energy form we are tapping into.
When I bring this copper pipe near my larger dual cones that do resonate up at 333 kHz, the cones vibrate up nicely.
However the height of the cones are 4.69 inches over spec, from what they should be, and do not fall in the "sweet spot" they should.

This means I need to find smaller wire, physically, but maintain the higher dielectric constant of the insulation to keep the frequency of resonance low.

I would also submit, there is no electronics formula out there, as of yet, that can be used to design the necessary properties of these dual cone systems.
Resonance frequency at the EM level must be found by trail and error for the wire type selected. Ham radio methods, with many people experimenting.
My first run provided much necessary information, as to how to proceed, but we are still left with trial and error factors on a final build that will work., based on past builds and measurements.

### Here are the factors of the design.

1 - The cone height 19.5756 inches
2 - The cone apex angle 33 degrees
3 - The cone wiring surface area 371.91513 square inches
4 - The size of the wire plus insulation which will determine if the wire can all fit in the correct space
5 - The dielectric constant of the wire which will shorten the resonant wire length
6 - The actual wire length, which will resonate the  EM frequency
7 - The Dual cones EM resonance frequency 333 kHz, after assembly and cross connection

I noted in my first document, the correct wire size may be difficult, or more expensive to locate.
Teflon coated wire, had the necessary dimension qualities, insulation is thinner, with moderate dielectric constant, but was very high in cost.

# Calculation Review In Depth

## Fractal Calculation

1.87 mm is the wavelength of the background field resonance in free space.
Now dealing with this length as a fractal vibration we start summing it to see how it fits the tetrahedron that Bashar offered us.

Perfect Tetrahedron height
1.87 mm x 489 = 914.43 mm  = 36.001 inches        This is a background coupling length at 489 times the fractal resonance of the space field.

Perfect Tetrahedron side length
1.87 mm x 598 = 1118.26 mm = 44.026 inches       This is another background coupling at 598 times the fractal resonance of the space field.

I cut each of these lengths above to verify they do vibrate up in copper tubes, and I can feel them with the palms.
These are the dimensions of the Source field resonance we are tapping into.

Energy on a fractal breaks down to the wavelength of the prime factors of the segment length stack number.
The vibration rises in frequency with more length, opposite as the EM wave where vibration frequency drops with longer length, and in this inversion of time into space is the real formula we are working with.
This effect of vibration rising in frequency stops when you hit a prime number length of the base fractal, causing a down shift of the higher vibration rate to a lower frequency.

489 = 163 x 3 both prime numbers. These will fracture into 3 lengths of exactly 1 foot in oscillation at the vibration level.
163 x 1.87 =  304.81 mm = 30.481 cm =12.000 inches.

598 = 2 x 13 x 23  all prime numbers. This fracturing is more complex with 3 different lengths of harmonic vibration present in the vibration field
1.87 x 13 =   24.31 mm = 2.431 cm  = 0.95708661 inch
1.87 x 23 =   43.01 mm = 4.301 cm = 1.693307 inch

## Geometry Calculation

Two different interpretations of Bashars descriptions of deriving the cone dimensions from the tetrahedron form have been noted, shown in the diagrams below.

The calculations here are from the lower interpretation. Believing the cone must fit inside the platonic solid form, as the cutaway on the right shows of the top view, where the cone intersects the tetrahedrons sides, the wire stays inside the form and cannot touch the outer corners of the tetrahedron. Note the difference is about 5.5 inches in the two cones heights.

## Find the actual cone dimensions accurately:

We begin with the dihedral angle of the tetrahedron form 70.53 degrees from geometry references.
This is the angle between the planar surfaces as they meet on the edges of the tetrahedron as located in the drawing above.

Table of polyhedron dihedral angles

Star Tetrahedron

From the star tetrahedron URL above, at the bottom of it's page, we find the angle very accurately calculated out to 70.52877937 degrees.
The other angle, where the star tetrahedrons opposing rotations hit a sphere, also used below, 19.4712263 degrees [for reference].
This is a point on the earths sphere said to be very active with torsion field energy, latitude 19.47 degrees.
For now simply note these two special angles add up to exactly 90 degrees and are used in the calculations below.

Also the relation of the long edge length 44" to the height of the tetrahedron 36" [ height  = sqrt (2/3) x edge length. ]
Wikipedia Tetrahedron

The first image below is a tetrahedron shown, with the height from the tip extended down to the center of the bottom, forming the triangles we will use to calculate the cone dimensions. From this we solve for the length of x, which will be one side of the smaller triangle the cone fits in. x = sin(60) * 44.026"  =  38.127".

The second image below is the small triangles in this area turned flat to the screen with angles and known lengths plotted for reference.
Tetrahedron height = 36.001" for a perfect space resonance. The height hits the bottom line at 1/3 of it's length, from the geometry data found on line.
The bottom two lengths are now derived from the 38.127" length cut into thirds. 12.708234 and 25.418766 inches.

The third image below at the bottom is a blow up of the small triangle forming the cones angles and lengths, that will just set inside the larger tetrahedron in 3D.
x y and z are the values we need to accurately find, to construct the cone with a 33 degree apex angle at the tip.

## Cone Set 1

### From the lower diagram, solving simultaneous equations, down the middle then continued up on the right, we come up with the actual cone dimensions x y z.

33 degree Cone

height z                      19.5756 "    =  49.7220 cm
side x                         20.41636 "  =   51.8575 cm
radius at base  y         5.79856"   =   14.72834 cm
diameter at base 2y  11.59712"   =  29.45668 cm

Up to this point everyone seems to be in agreement and understanding fairly closely. However, here is where many get into totally absurd spin offs, that cannot begin to work for an EM extraction. Winding a coil with random size of wire and turns, will not produce a resonating EM field.

We must follow up with the Electrical Specifications to match the geometry and resonate the Electro-Magnetic field at 333kHz in order for the background vibration field to couple to it.

## Find the area of the surface of the cone that the wire will have to geometrically fit inside

Area of a cones surface =   pi * r * s     [s = side length]

r = 5.79856 "
s = 20.41636 "

Area = 371.91513 square inches

This is now our Geometric Space Resonant wiring surface.
The wire must fit in this area.
We can use this formula to test our coil designs for a good fit.
Wire length times wire diameter = Cone surface area

[W len * W dia  = 371.91513 square inches.]

## Cone Set 2

### In the second case, we have the larger interpretation providing the data below.

This is the size of my cone set 2 data, the larger cones.

# EM Resonance

### Parameters of Consequence

The coils we wind on the surface area of the two cones, when connected together top and bottom, must vibrate up the electromagnetic field at 333 kHz exactly, as a current flow. [333000 Hz]

Here is the frequency response of the target coil system

The coil system has a negative dip at resonance, it's reactance drops drastically and sharply at the one frequency it is tuned to.
The coil reduces noise by eliminating "currents" of off resonant frequencies, and only passes one frequency as a "current source."

A coil at the center, as a secondary, has a reversed curve as above, and converts the signal to a peaking voltage at resonance.
See diagrams below.

The resonant frequency can vary depending on the impedance of the feed to it.
Fed into a detector and audio amplifier, it can produce an output that has less background noise then a commercial radio receiver, and pick up stations with greater clarity.
See diagram below.

This shows how the coil system is different then conventional coils.
The distributed capacitance and inductance along the windings change the resonant qualities of the coil system inverting it to resemble a series tuned circuit.

## Wire Choices

### Wire diameter times Wire length  =  Wire surface area

The Wire must fit on cone surface area, as close as possible for the greatest coupling of energy on the "sweet spot" of the vibration nodes.
Once we know the length of the resonant wire, we can calculate the maximum wire size diameter by dividing it's length into the surface area.
Wire plus insulation must be equal to or less then this diameter value.

Wire max diameter = 371.91513 / Wire Length

### Wire dielectric constant or VOP [velocity of propagation] x  wire length = EM wavelength / 2   at  333 kHz

To find the length of the wire, we must multiply the VOP [velocity of propagation] times the free space resonance wavelength of a 333 kHz EM resonant RF field, then divide by 2 to get the 1/2 wave length of each coil.

c = light velocity = 299792458 meters per second

Wire Length = VOP * (c / 333000 Hz) / 2)
Wire Length = VOP *  (900.27765 meters / 2)

First wire length calculation free space dipole antenna resonance at 333000 Hz

Wire Length = VOP *  450.1388258 meters in free space

Convert to cm then Inches then Feet
Wire Length = VOP *   45,013.88258 centimeters
Wire Length = VOP *  17,722.001 inches
Wire Length = VOP *  1,476.833417979 feet

We end up with a range of possible wire lengths based on past experience with insulated wire for a free space dipole antenna.

.5 to .3 VOP
W len = .5 * 1476.833417979 feet = 738.4167089 feet
W len = .3 * 1476.833417979 feet = 443.0500254 feet

### EM resonance on Completed Joined Cones = 333 kHz exactly

The wire length on a wound coil is much shorter then the free space antenna wire length.
In some coil calculators it is 1/4 wave rather then 1/2 wave, as the ends are terminated rather then opened inverting the reflected signal polarity.
This cuts our wire length in half again for the dual coil system.
220 to  369 feet range for wire lengths with high moderate dielectric insulation

Early testing showed this is likely true.
500 feet PVC wire on a shipping spool resonated at 153.843 kHz    [less then 1/2 what is calculated above for a free space antenna]
Two of these coils in parallel connection resonated at 163.934 kHz
Only a 10.091 kHz increase and no where even near 333.000 kHz target resonance, from a free space dipole with opened ends.
166.5 kHz is 1/2 of 333 kHz
Thus for a 333 kHz wave on a dual coil system, using this wire, we would expect about 255 feet should be close for each coil.

The resonant frequency on these cones is a lower resistance, like a series resonant circuit. As you tune across the band the voltage will dip sharply at resonance, indicating a higher current condition as a load.
A center positioned secondary coil will peak in voltage at the same time. In this sense it acts like a transformer.

[I have 3 dual cone sets to measure the following parameters for the 2 mm diameter wire that was used]
Wire length per cone
Number of turns per cone
R0 frequency - per finished cones in parallel

After I get this data recorded here, we can move forwards with a next best guess on wire choice and quantity for a more accurate build of the dual cone system.

### Notes:

On the dual cone assembly the ends of the antenna are shorted, so the voltage wave will flip over or toggle on the two ends as it is reflected back and forth.
This makes the coil system an oscillator, rather then an antenna, technically.

It is all about having the 333 kHz EM wave move end to end of the coll system at exactly the correct timing, split through both coils, so that voltage nodes develop on both ends of the coils simultaneously, and current nodes at the center crossing point.
As the voltage wave starts at one end of the coils it must move to the other end at 1/2 wavelength and then return at 1 wavelength to resonate as an oscillator, or generator of AC power.
Both coils must have the same exact wire length as well for this to happen consistently over time, otherwise there will be drift of the nodes and then loss of synchronization with the background space field.
Sloppy wiring, or inconsistency between the two coils will likely cause the voltage nodes to drift out of sync. Anything less then perfection will likely not self oscillate.
To compensate for this, the joining wires at one end may be lengthened or shortened.

These are the parameters of consequence, which will "make or break" the system resonance, and the conversion of vibration into EM field power.

Cone Set 2 Data

## Maximizing the Earth Ground Wave

There are several suggestions that can increase the vibrational energy in the dual cone system, that have been shown to work on the vibration side of the energy form.

The first is to mount the dual cones over an earth node. The vibration energy that actually powers the field comes from the earths mass.
Mount them centered over an earth node and then raise and lower them for a peak of vibration on the cones.

The next possibility is to set up a copper tube tetrahedron antenna system with 44.026" sides.
If set up over an earth node at correct height, this antenna system should greatly increase the vibration field strength of the dual cones.
The apex is routed via copper wire to a tuning gap over the top of the cones cross wired ends. The gap can be any multiple of 1.87 mm, and the energy should jump into the cones.
This will keep raw voltage off the antenna, and yet allow a free flow of vibration energy across the gap. If you need more spacing increase it by steps of 1.87 mm [background resonance of the Ether medium].
The same can be at done the bottom of the cone into an earth ground, allowing the voltage on the cones to be free of the earth, and still pass the vibration energy through them.

Dave L   3 / 14 / 2015